This is really a return to a problem I addressed over a year ago. It came up again, quite by chance, and I came up with another proof that makes my original post … almost embarrasing.
The idea is that for n = 0, 1, 2, 3, …, for numbers of the form
their squares contain no zeroes.
For example, for n = 1, (10 + 2)/3 = 4, and 4*4 = 16, 16 contains no 0’s. But the same holds for -all- n, none of the squares contain 0’s.
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